Matematica esercizio 181,182,184

182 

angolo LNM = arccos 2√2 /3 = 19,4712°

sen LNM = sen 19,4712° = 1/3 

angolo NML = 180-(30+19,4712) = 130,5288°

seno 130,5288° = 0,760

60/ (1/3) = MN/0,5

MN = 30/(1/3) = 90 cm 

60/ (1/3) = LN/0,760

LN = 180*0,760 = 136,814 

check = 30*(2*2^0,5+3^0,5) = 136,814

181

DAB = 60°

ABD = 45°

ADB = 75°

12/sen 60° = AD/sen 45°

AD = 12*√2 /2  /( √3 /2)  = 12√2 / √3

sen 75 = sen(30+45) = 0,5*√2 /2 + √3 /2*√2 /2 = √2(1+√3)/4

12/sen 60° = AB/sen 75°

AB = 12(√2(1+√3)/4)*2/√3 = 3(√2(1+√3) / √3 

perimetro = 2(AD+AB) = 2(12√2+3(√2(1+√3))) / √3