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Spigolo $s= \sqrt{\dfrac{Al}{4\,facce}} = \sqrt{\dfrac{27,04}{4}} = 2,6\,dm;$
volume $V= s^3 = 2,6^3 = 2,6×2,6×2,6 = 17,576\,dm^3;$
massa $m= V×d = 17,576\,\cancel{dm^3}×2,5\,\dfrac{kg}{\cancel{dm^3}} = 43,94\,kg.$