[Risolto] Esponenziali

(2^(-x) + 2^1 * 2^(-x))/3 = 5^(x+2)/5^(2x+2)

2^(-x) * (1+2)/3 = 5^(-x)

2^(-x)/5^(-x) = 3/3

(5/2)^x = 1

(5/2)^x = (5/2)^0

x = 0