[Risolto] Problema di geometria

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Area della figura:

$A= 2·4+\dfrac{4^2·\pi}{4}+\dfrac{3^2·\pi}{2·4}+\dfrac{2^2·\pi}{2·4}$

$A= 8+\dfrac{\cancel{16}^4·\pi}{\cancel4_1}+\dfrac{9·\pi}{8}+\dfrac{4·\pi}{8}$

$A= 8+4\pi+\dfrac{13}{8}\pi$

$A\approx{25,67}\,cm^2.$