A volleyball is spiked so that its incoming velocity of $+4.0 \mathrm{~m} / \mathrm{s}$ is changed to an outgoing velocity of $-21 \mathrm{~m} / \mathrm{s}$. The mass of the volleyball is $0.35 \mathrm{~kg}$.
- What impulse does the player apply to the ball?
$[-8.75 \mathrm{~kg}-\mathrm{mi} / \mathrm{s}\}$
8
punti
Livello 0
Teorema dell'impulso
F*dt = m*(V_finale - V_iniziale)
L'impulso (grandezza vettoriale, I= F*dt [N*s]) trasmesso è pari alla variazione di quantità di moto.
I= - 8,75 N*s
77016
punti
Genius II
@stefanopescetto 👍👌👍
A volleyball is spiked so that its incoming velocity of +4.0 m/s is changed to an outgoing velocity of −21 m/s. The mass m of the volleyball is 0.35 kg.
- What impulse I does the player apply to the ball? [−8.75 kg −mi/s}
Impulse I = m*ΔV = 0,35*(-21-4) = -8,75 kg*mps
142399
punti
Genius III
