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0

A volleyball is spiked so that its incoming velocity of $+4.0 m / s$ is changed to an outgoing velocity of $-21 m / s$. The mass of the volleyball is $0.35 kg$.
What impulse does the player apply to the ball?
$$
[-8.75 kg \cdot m / s ]
$$

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3

Fm*dt = m*(V_finale - V_iniziale) 

Legge vettoriale 

 

Sostituendo i valori numerici otteniamo 

Screenshot 20230529 163217

I= - 8,75 N*s

 

 

@stefanopescetto 👍👌👍



2

A volleyball is spiked so that its incoming velocity of +4.0⁢𝑚/𝑠 is changed to an outgoing velocity of −21⁢𝑚/𝑠. The mass m of the volleyball is 0.35⁢𝑘⁢𝑔.
What impulse I does the player apply to the ball? [−8.75⁢𝑘⁢𝑔⋅𝑚/𝑠]

 

Impulse I = m*ΔV = 0,35*(-21-4) = -8,75 kg*mps



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