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problema sull’elettromagnetismo

  

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1

 B =  μo * i /(2πr);   Legge sperimentale di Biot e Savart.

ko = μo/2π =  2 * 10^-7 N /A^2;

B = ko * i / r

B risultante = ko  i1 / r1 + ko i2 / r2  + ko i3/r2;

r1 = 2,0 cm = 2,0 * 10^-2 m; r2 = 5,0 cm; r3 = 8,0 cm

In A:

B1 entrante in A; B2 uscente in A; B3 entrante in A;

B1 = 2 * 10^-7 * 1,0 /(2,0 * 10^-2); entrante (+)

B2 = 2 * 10^-7 * 2,0 /(5,0 * 10^-2); uscente (-)

B3 = 2 * 10^-7 * 4,0 /(8,0 * 10^-2); entrante (+);

B(in A) = B1 - B2 + B3 ;

 

B (in A) = 2 * 10^-7 * [1,0 /(2,0 * 10^-2) - 2,0 /(5,0 * 10^-2) + 4,0 /(8,0 * 10^-2)];

B (in A) = 2 * 10^-7 * [50 - 40 + 50] = 2 * 10^-7 * 60;

B(in A) = 1,2 * 10^-5 T = 12,0 μT; entrante in A



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