Problema Matematica

(3/2 * a + 1/3 * b) * (4/5 * a)  + (a + b^2) /[3 * (a - b)];

a = 1/3;  b = - 2/3.

3/2 * a = 3/2 * 1/3 = 1/2;

1/3 * b = 1/3 * (- 2/3) = - 2/9,

4/5 * a = 4/5 * 1/3 = 4/15;

b^2 = (-2/3)^2 = + 4/9;

(1/2 - 2/9) * 4/15 + (1/3 + 4/9) / [3 * (1/3 + 2/3)] =

= [(9 - 4)/18] * 4/15 + [(3 + 4) /9] / [3 * (3/3)] =

= [5/18] * 4/15 + (7/9) / (3 * 1) =

= 2/27  + (7/9) * 1/3 =

= 2/27 + 7/27 =

= 9/27 = 1/3;

Ciao  @ciaoamico