[Risolto] Potreste aiutarmi con questa espressione con le frazioni, i numeri relativi e le potenze?Grazie.Il risultato è -59/32.

$15\left\{-\left(\frac{2}{5}+2\right)-\left(\frac{2}{5}-3\right)-\frac{3}{4}÷\frac{1}{3}-\left[\left(\frac{2}{5}+1\right)÷\left(5-\frac{8}{3}\right)-\frac{2}{3}\right]÷\left(-\frac{4}{3}\right)\right\}\left(-\frac{1}{4}\right)^2-\left(-\frac{1}{2}\right)^3=$

$=15·\left\{-\left(\frac{2+10}{5}\right)-\left(\frac{2-15}{5}\right)-\frac{3}{4}·3-\left[\left(\frac{2+5}{5}\right)÷\left(\frac{15-8}{3}\right)-\frac{2}{3}\right]·\left(-\frac{3}{4}\right)\right\}·\frac{1}{16}-\left(-\frac{1}{8}\right)=$

$=15·\left\{-\frac{12}{5}-\left(-\frac{13}{5}\right)-\frac{9}{4}-\left[\frac{7}{5}÷\frac{7}{3}-\frac{2}{3}\right]·\left(-\frac{3}{4}\right)\right\}·\frac{1}{16}+\frac{1}{8}=$

$=15·\left\{-\frac{12}{5}+\frac{13}{5}-\frac{9}{4}-\left[\frac{\cancel7^1}{5}·\frac{3}{\cancel7_1}-\frac{2}{3}\right]·\left(-\frac{3}{4}\right)\right\}·\frac{1}{16}+\frac{1}{8}=$

$=15·\left\{\frac{1}{5}-\frac{9}{4}-\left[\frac{1}{5}·\frac{3}{1}-\frac{2}{3}\right]·\left(-\frac{3}{4}\right)\right\}·\frac{1}{16}+\frac{1}{8}=$

$=15·\left\{\frac{1}{5}-\frac{9}{4}-\left[\frac{3}{5}-\frac{2}{3}\right]·\left(-\frac{3}{4}\right)\right\}·\frac{1}{16}+\frac{1}{8}=$

$=15·\left\{\frac{1}{5}-\frac{9}{4}-\left[\frac{9-10}{15}\right]·\left(-\frac{3}{4}\right)\right\}·\frac{1}{16}+\frac{1}{8}=$

$=15·\left\{\frac{1}{5}-\frac{9}{4}-\left[-\frac{1}{15}\right]·\left(-\frac{3}{4}\right)\right\}·\frac{1}{16}+\frac{1}{8}=$

$=15·\left\{\frac{1}{5}-\frac{9}{4}+\frac{1}{\cancel{15}_5}·\left(-\frac{\cancel3^1}{4}\right)\right\}·\frac{1}{16}+\frac{1}{8}=$

$=15·\left\{\frac{1}{5}-\frac{9}{4}-\frac{1}{20}\right\}·\frac{1}{16}+\frac{1}{8}=$

$=15·\left\{\frac{4-45-1}{20}\right\}·\frac{1}{16}+\frac{1}{8}=$

$=15·\left\{-\frac{\cancel{42}^{21}}{\cancel{20}_{10}}\right\}·\frac{1}{16}+\frac{1}{8}=$

$=15·\left\{-\frac{21}{10}\right\}·\frac{1}{16}+\frac{1}{8}=$

$=\cancel{15}^3·\left\{-\frac{21}{\cancel{10}_2}\right\}·\frac{1}{16}+\frac{1}{8}=$

$=3·\left\{-\frac{21}{2}\right\}·\frac{1}{16}+\frac{1}{8}=$

$=-\frac{63}{2}·\frac{1}{16}+\frac{1}{8}=$

$=-\frac{63}{32}+\frac{1}{8}=$

$=\frac{-63+4}{32}=$

$=-\dfrac{59}{32}$

 

 

 

15 • {- (⅖ + 2) - (⅖ - 3)- ¾ : ⅓- [ (⅖ + 1) : (5 - 8/3) - ⅔ ] : (- 4/3)} • (- ¼ )² - (- ½)³ = [-59/32]

15 * {- (2/5 + 10/5) - (2/5 - 15/5) - 3/4 : 1/3 - [(2/5 + 5/5) : (15/3- 8/3) - 2/3]:(- 4/3)} * (+1/16) - (-1/8);

15 * {- 12/5 - (-13/5) - 3/4 : 1/3 - [7/5 : 7/3 - 2/3] : (- 4/3)}* 1/16 + 1/8;

15 * {- 12/5 + 13/5 - 3/4 * 3/1 - [7/5 * 3/7 - 2/3] : (- 4/3) } * 1/16 + 1/8;

15 * {-12/5 + 13/5 - 9/4 -  [3/5 - 2/3] : (- 4/3) } * 1/16 + 1/8;

15 * {- 12/5 + 39/5 - 9/4 -  [9/15 - 10/15] : (- 4/3) } * 1/16 + 1/8;

15 * {- 48/20 + 52/20 - 45/20 + 1/15 * (- 3/4)} * 1/16 + 1/8;

15 * {- 48/20 + 52/20 - 45/20 - 1/20} * 1/16 + 1/8;

15 * { - 42/20} * 1/16 + 1/8;

15 *{- 21/10} * 1/16 + 1/18;

3 * {- 21/2} * 1/16 + 1/8

- 63/32 + 1/8 =

= - 63/32 + 4/32 = - 59/32

Ciao @lya

ho corretto.