N. 503

Question

[(1/10+1/5)×(1/9+1/3)] : (2+1/5-1)+2/9=

gramor · Accepted Answer

big [ big ( frac {1}{10}+ frac {1}{5} big ) big ( frac {1}{9}+ frac {1}{3} big ) big ] :  big (2+ frac {1}{5}-1 big )+ frac {2}{9} = =  big [ big ( frac {1+2}{10} big ) big ( frac {1+3}{9} big ) big ] :  big ( frac {10+1-5}{5} big )+ frac {2}{9} = =  big [ frac {3}{10}× frac {4}{9} big ] :  frac {6}{5}+ frac {2}{9} = =  big [ frac {1}{5}× frac {2}{3} big ] ×  frac {5}{6}+ frac {2}{9} = =  frac {2}{15} ×  frac {5}{6}+ frac {2}{9} = =  frac {1}{3} ×  frac {1}{3}+ frac {2}{9} = =  frac {1}{9}+ frac {2}{9}= frac {3}{9}= frac {1}{3}

N. 503

Domande