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[Risolto] N. 504

  

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[7-1/3-(3/2-2)]×4/3+5/6-22×1/2+1/8=

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$\big[7-\frac{1}{3}-\big(\frac{3}{2}-2\big)\big]×\frac{4}{3}+\frac{5}{6}-22×\frac{1}{2}+\frac{1}{8}$ =

= $\big[7-\frac{1}{3}-\big(\frac{3-4}{2}\big)\big]×\frac{4}{3}+\frac{5}{6}-11×\frac{1}{1}+\frac{1}{8}$ =

= $\big[7-\frac{1}{3}-\big(-\frac{1}{2}\big)\big]×\frac{4}{3}+\frac{5}{6}-11+\frac{1}{8}$ =

= $\big[7-\frac{1}{3}+\frac{1}{2}\big]×\frac{4}{3}+\frac{5}{6}-11+\frac{1}{8}$ =

= $\big[\frac{42-2+3}{6}\big]×\frac{4}{3}+\frac{5}{6}-11+\frac{1}{8}$ =

= $\frac{43}{6}×\frac{4}{3}+\frac{5}{6}-11+\frac{1}{8}$ =

= $\frac{43}{3}×\frac{2}{3}+\frac{5}{6}-11+\frac{1}{8}$ =

= $\frac{86}{9}+\frac{5}{6}-11+\frac{1}{8}$ =

= $\frac{688+60-792+9}{72}= -\frac{35}{72}$

@gramor grazie mille di tutto

@Margherit - Grazie, molto gentile, cordiali saluti.



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