ho bisogno come si calcolano le aree degli ultimi due grazie
Foto dritta!!!
2·(2·(2·x + 3 + 2)) - 2^2 = 8·x + 16
(3·x + 2)^2 + (3·x + 1)·(3·x + 2 - 3) = 18·x^2 + 12·x + 3
(3·x + 5)·(2·x + 3) - (3·x + 5 - 4)·(2·x + 3 - 2) = 14·x + 14
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11/2
Area parte colorata:
$\small A= (3x+2)(3x+2)+(3x+1)(3x+2-3)$
$\small A= 9x^2+6x+6x+4+(3x+1)(3x-1)$
$\small A= 9x^2+12x+4+9x^2\cancel{-3x}\cancel{+3x}-1$
$\small A= 18x^2+12x+3$
(a+b) = 75/2 m
a*b = 250 m^2
(250/b+b) = 75/2
(250+b^2) = 75b/2
250+b^2-75/2b = 0
b = (75/2±√75^2/4-1000)/4 = 8,672 ; a = 28,828 m
A' = (a+4)^2*(b+4)^2 = 12,672*32,828 = 416,00 m^2
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11/3
Area parte colorata:
$\small A= (2x+3)(3x+5)-(3x+5-2·2)(2x+3-2·1)$
$\small A= 6x^2+10x+9x+15-(3x+5-4)(2x+3-2)$
$\small A= 6x^2+19x+15-(3x+1)(2x+1)$
$\small A= 6x^2+19x+15-(6x^2+3x+2x+1)$
$\small A= 6x^2+19x+15-(6x^2+5x+1)$
$\small A= \cancel{6x^2}+19x+15\cancel{-6x^2}-5x-1$
$\small A= 19x+15-5x-1$
$\small A= 14x+14$