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Ex 2

  

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IMG 7325
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3
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sopra la linea di frazione :

4*3/8 - 1 = 1/2

sotto la linea di frazione

7/6*6*3/14 = 3/2

 

3/4 * 1/2*2/3 + 1

3/4*1/3 + 1

1/4 + 1 

5/4 

 

@remanzini_rinaldo 

👍 👍 👍 



3

3/4·(4/(5/3 + 1) - 1)/((2/3 + 1/2)/(2/3 - 1/2)·3/14) + 1=

=3/4·(4/(8/3) - 1)/(7/6/(1/6)·3/14) + 1=

=3/4·(3/2 - 1)/(7·3/14) + 1=

=3/4·(1/2)/(3/2) + 1=

=3/8/(3/2) + 1=

=1/4 + 1 = 5/4

@lucianop 👍👌👍



1
image

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$\small = \dfrac{3}{4}×\dfrac{\dfrac{4}{\dfrac{5}{3}+1}-1}{\dfrac{\dfrac{2}{3}+\dfrac{1}{2}}{\dfrac{2}{3}-\dfrac{1}{2}}×\dfrac{3}{14}}+1 = $

$\small = \dfrac{3}{4}×\dfrac{\dfrac{4}{\dfrac{5+3}{3}}-1}{\dfrac{\dfrac{4+3}{6}}{\dfrac{4-3}{6}}×\dfrac{3}{14}}+1 = $

$\small = \dfrac{3}{4}×\dfrac{\dfrac{4}{\dfrac{8}{3}}-1}{\dfrac{\dfrac{7}{6}}{\dfrac{1}{6}}×\dfrac{3}{14}}+1 = $

$\small = \dfrac{3}{4}×\dfrac{\cancel4^1×\dfrac{3}{\cancel8_2}-1}{\dfrac{\cancel7^1}{\cancel6_1}×\cancel6^1×\dfrac{3}{\cancel{14}_2}}+1 = $

$\small = \dfrac{3}{4}×\dfrac{1×\dfrac{3}{2}-1}{\dfrac{1}{1}×1×\dfrac{3}{2}}+1 = $

$\small = \dfrac{3}{4}×\dfrac{\dfrac{3}{2}-1}{\dfrac{3}{2}}+1 = $

$\small = \dfrac{3}{4}×\dfrac{\dfrac{3-2}{2}}{\dfrac{3}{2}}+1 = $

$\small = \dfrac{3}{4}×\dfrac{\dfrac{1}{2}}{\dfrac{3}{2}}+1 = $

$\small = \dfrac{\cancel3^1}{4}×\dfrac{1}{\cancel2_1}×\dfrac{\cancel2^1}{\cancel3_1}+1 = $

$\small = \dfrac{1}{4}×\dfrac{1}{1}×\dfrac{1}{1}+1 = $

$\small = \dfrac{1}{4}+1 = $

$\small = \dfrac{1+4}{4} = $

$\small = \dfrac{5}{4} $



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