Aiutatemi a risolvere le espressioni,grazie)
(7/4·(2/3 - 2/7) + (1/2)^2)/(1 - 7/12)/x = x/((8/11·(3/2 + 1/3) - 4/5·(3/4))/(2/3·2))
(7/4·(8/21) + 1/4)/(1 - 7/12)/x = x/((8/11·(3/2 + 1/3) - 4/5·(3/4))/(2/3·2))
(7/4·(8/21) + 1/4)/(5/12)/x = x/((8/11·(11/6) - 3/5)/(4/3))
(2/3 + 1/4)/(5/12)/x = x/((4/3 - 3/5)/(4/3))
11/12/(5/12)/x = x/(11/15/(4/3))
11/5/x = x/(11/20)
x^2 = 11/5·(11/20)
x^2 = 121/100-----> x = 11/10
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(3/5 + 1/10/(2/5))/x = (5/8 + 1/2 - 1/8·(3/5)^2)/((2/3 + 1/4)/(5/12 - 1/9))
(3/5 + 1/4)/x = (5/8 + 1/2 - 1/8·(9/25))/(11/12/(11/36))
17/20/x = (5/8 + 1/2 - 9/200)/3
17/20/x = 27/25/3
x = 17/20·3/(27/25)
x = 51/20/(27/25)
x = 85/36
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$\small \left\{\left[\dfrac{7}{4}·\left(\dfrac{2}{3}-\dfrac{2}{7}\right)+\left(\dfrac{1}{2}\right)^2\right]÷\left(1-\dfrac{7}{12}\right)\right\}÷x=x÷\left\{\left[\dfrac{8}{11}·\left(\dfrac{3}{2}+\dfrac{1}{3}\right)-\dfrac{\cancel4^1}{5}·\dfrac{3}{\cancel4_1}\right]÷\left(\dfrac{2}{3}·2\right)\right\}$
$\small \left\{\left[\dfrac{7}{4}·\left(\dfrac{14-6}{21}\right)+\dfrac{1}{4}\right]÷\left(\dfrac{12-7}{12}\right)\right\}÷x=x÷\left\{\left[\dfrac{8}{11}·\left(\dfrac{9+2}{6}\right)-\dfrac{1}{5}·\dfrac{3}{1}\right]÷\dfrac{4}{3}\right\}$
$\small \left\{\left[\dfrac{\cancel7^1}{\cancel4_1}·\dfrac{\cancel8^2}{\cancel{21}_3}+\dfrac{1}{4}\right]÷\dfrac{5}{12}\right\}÷x=x÷\left\{\left[\dfrac{\cancel8^4}{\cancel{11}_1}·\dfrac{\cancel{11}^1}{\cancel6_3}-\dfrac{3}{5}\right]·\dfrac{3}{4}\right\}$
$\small \left\{\left[\dfrac{1}{1}·\dfrac{2}{3}+\dfrac{1}{4}\right]·\dfrac{12}{5}\right\}÷x=x÷\left\{\left[\dfrac{4}{1}·\dfrac{1}{3}-\dfrac{3}{5}\right]·\dfrac{3}{4}\right\}$
$\small \left\{\left[\dfrac{2}{3}+\dfrac{1}{4}\right]·\dfrac{12}{5}\right\}÷x=x÷\left\{\left[\dfrac{4}{3}-\dfrac{3}{5}\right]·\dfrac{3}{4}\right\}$
$\small \left\{\left[\dfrac{8+3}{12}\right]·\dfrac{12}{5}\right\}÷x=x÷\left\{\left[\dfrac{20-9}{15}\right]·\dfrac{3}{4}\right\}$
$\small \left\{\dfrac{11}{\cancel{12}_1}·\dfrac{\cancel{12}^1}{5}\right\}÷x=x÷\left\{\dfrac{11}{\cancel{15}_5}·\dfrac{\cancel3^1}{4}\right\}$
$\small \left\{\dfrac{11}{1}·\dfrac{1}{5}\right\}÷x=x÷\left\{\dfrac{11}{5}·\dfrac{1}{4}\right\}$
$\small \dfrac{11}{5}÷x=x÷\dfrac{11}{20}$
$\small x·x=\dfrac{11}{20}·\dfrac{11}{5}$
$\small x^2=\dfrac{121}{100}$
$\small \sqrt{x^2}=\sqrt{\dfrac{121}{100}}$
$\small x=\dfrac{11}{10}$
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$\small \left(\dfrac{3}{5}+\dfrac{1}{10}÷\dfrac{2}{5}\right)÷x=\left[\dfrac{5}{8}+0,5-\dfrac{1}{8}·\left(\dfrac{3}{5}\right)^2\right]÷\left[\left(\dfrac{2}{3}+\dfrac{1}{4}\right)÷\left(\dfrac{5}{12}-\dfrac{1}{9}\right)\right]$
$\small \left(\dfrac{3}{5}+\dfrac{1}{\cancel{10}_2}·\dfrac{\cancel5^1}{2}\right)÷x=\left[\dfrac{5}{8}+\dfrac{\cancel5^1}{\cancel{10}_2}-\dfrac{1}{8}·\dfrac{9}{25}\right]÷\left[\left(\dfrac{8+3}{12}\right)÷\left(\dfrac{45-12}{108}\right)\right]$
$\small \left(\dfrac{3}{5}+\dfrac{1}{2}·\dfrac{1}{2}\right)÷x=\left[\dfrac{5}{8}+\dfrac{1}{2}-\dfrac{9}{200}\right]÷\left[\dfrac{11}{12}÷\dfrac{33}{108}\right]$
$\small \left(\dfrac{3}{5}+\dfrac{1}{4}\right)÷x=\left[\dfrac{125+100-9}{200}\right]÷\left[\dfrac{\cancel{11}^1}{\cancel{12}_1}·\dfrac{\cancel{108}^9}{\cancel{33}_3}\right]$
$\small \left(\dfrac{12+5}{20}\right)÷x=\dfrac{\cancel{216}^{27}}{\cancel{200}_{25}}÷\left[\dfrac{1}{1}·\dfrac{\cancel9^3}{\cancel3_1}\right]$
$\small \dfrac{17}{20}÷x=\dfrac{27}{25}÷\dfrac{3}{1}$
$\small x= \dfrac{17}{20}·3÷\dfrac{27}{25}$
$\small x= \dfrac{\cancel{51}^{17}}{\cancel{20}_4}·\dfrac{\cancel{25}^5}{\cancel{27}_9}$
$\small x= \dfrac{17}{4}·\dfrac{5}{9}$
$\small x= \dfrac{85}{36}$