[(2-1)x7+5] ÷ [3-(1-1)] + [15-3x(1+2)]
[(2-1)x7+5] ÷ [3-(1-1)] + [15-3x(1+2)]
((2 - 1)·7 + 5)/(3 - (1 - 1)) + (15 - 3·(1 + 2))=
=12/3 + (15 - 9)= 4 + 6 = 10
[(2-1)x7+5] ÷ [3-(1-1)] + [15-3x(1+2)]
[1x7+5]:[3-0]+[15-3x3]
12:3+6= 4+6= 10
$[(2-1)×7+5] ÷ [3-(1-1)]+[15-3(1+2)] $ =
= $[1×7+5] ÷ [3-0]+[15-3×3] $ =
= $[7+5] ÷ 3 +[15-9] $ =
= $12 ÷ 3 + 6$ =
= $4+6$ =
= $10$