{(2+7-3x2) x [4-(1+2)]} ÷ [7-(3x2+0)]
{(2+7-3x2) x [4-(1+2)]} ÷ [7-(3x2+0)]
(2 + 7 - 3·2)·(4 - (1 + 2))/(7 - (3·2 + 0))=
=(2 + 7 - 6)·(4 - 3)/(7 - 6)=
=3·1/(7 - 6)=3·1/1= 3
$\{(2+7-3×2) × [4-(1+2)]\} ÷ [7-(3×2+0)]$ =
= $\{(9-6)×[4-3]\} ÷ [7-6]$ =
= $\{3×1\} ÷ 1$ =
= $3 ÷ 1$ =
= $3$