65
punti
Livello 1
LOG(10,x) - 1/2 = LOG(10,√x)
C.E. x > 0
poniamo:
LOG(10,x) = t---> x = 10^t
LOG(10,√x) = 1/2·t
quindi:
t - 1/2 = 1/2·t---> 1/2·t = 1/2----> t = 1
x = 10^1----> x = 10
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LOG(2,x^2) + LOG(2,x)^2 = 0
2·LOG(2,x) + LOG(2,x)^2 = 0
C.E. x > 0
poniamo: LOG(2,x) = t---> x = 2^t
2·t + t^2 = 0---> t·(t + 2) = 0
t = -2 ∨ t = 0
x = 2^(-2)---> x = 1/4
x = 2^0----> x = 1
115471
punti
Genius III