2/3[(2x-1)(x-4)+3(x-1/3)(1/3+x)]=2/3(5x^2-x)+14/9
2/3[(2x-1)(x-4)+3(x-1/3)(1/3+x)]=2/3(5x^2-x)+14/9
103
punti
Livello 1
2/3[(2x-1)(x-4)+3(x-1/3)(1/3+x)]=2/3(5x^2-x)+14/9
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$\dfrac{2}{3}\left[(2x-1)(x-4)+3\left(x-\dfrac{1}{3}\right)\left(\dfrac{1}{3}+x \right) \right] =\dfrac{2}{3}\left(5x^2-x\right)+\dfrac{14}{9}$
$mcm= 9$ quindi:
$6\left[2x^2-8x-x+4+3\left(\cancel{\dfrac{1}{3}x}+x^2-\dfrac{1}{9}-\cancel{\dfrac{1}{3}x} \right) \right] =6\left(5x^2-x\right)+14$
$6\left[2x^2-9x+4+3\left(x^2-\dfrac{1}{9}\right)\right]=30x^2-6x+14$
$6\left[2x^2-9x+4+3x^2-\dfrac{\cancel3^1}{\cancel9_3}\right]=30x^2-6x+14$
$6\left[5x^2-9x+4-\dfrac{1}{3}\right]=30x^2-6x+14$
$30x^2-54x+24-\dfrac{\cancel6^2}{\cancel3_1}=30x^2-6x+14$
$30x^2-54x+24-2=30x^2-6x+14$
$30x^2-54x+22=30x^2-6x+14$
$\cancel{30x^2}\cancel{-30x^2}-54x+6x=14-22$
$-48x = -8$
$48x = 8$
$\dfrac{48x}{48}=\dfrac{\cancel8^1}{\cancel{48}_6}$
$x= \dfrac{1}{6}$
68277
punti
Genius I