@sabrina91 ---hai presente come si avvolge ? Si svolge in modo del tutto inverso 😉
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$\small \left[\dfrac{5}{2}·\dfrac{3}{2}-\left(\dfrac{3}{2}\right)^2 : \dfrac{3}{2}\right]·\left(\dfrac{4}{3} : \dfrac{4}{5}-\dfrac{\cancel{26}^{13}}{3}·\dfrac{1}{\cancel8_4}\right)=$
$\small =\left[\dfrac{15}{4}-\dfrac{9}{4} · \dfrac{2}{3}\right]·\left(\dfrac{4}{3} · \dfrac{5}{4}-\dfrac{13}{3}·\dfrac{1}{4}\right)=$
$\small =\left[\dfrac{15}{4}-\dfrac{\cancel9^3}{\cancel4_2} · \dfrac{\cancel2^1}{\cancel3_1}\right]·\left(\dfrac{\cancel4^1}{3} · \dfrac{5}{\cancel4_1}-\dfrac{13}{12}\right)=$
$\small =\left[\dfrac{15}{4}-\dfrac{3}{2} · \dfrac{1}{1}\right]·\left(\dfrac{1}{3} · \dfrac{5}{1}-\dfrac{13}{12}\right)=$
$\small =\left[\dfrac{15}{4}-\dfrac{3}{2} \right]·\left(\dfrac{5}{3}-\dfrac{13}{12}\right)=$
$\small =\left[\dfrac{15-6}{4} \right]·\left(\dfrac{20-13}{12}\right)=$
$\small =\dfrac{9}{4} ·\dfrac{7}{12}=$
$\small =\dfrac{\cancel9^3}{4} ·\dfrac{7}{\cancel{12}_4}=$
$\small =\dfrac{3}{4} ·\dfrac{7}{4}=$
$\small =\dfrac{21}{16}$