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Come si svolge

  

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@sabrina91 ---hai presente come si avvolge ? Si svolge in modo del tutto inverso 😉

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$\small \left[\dfrac{5}{2}·\dfrac{3}{2}-\left(\dfrac{3}{2}\right)^2 : \dfrac{3}{2}\right]·\left(\dfrac{4}{3} : \dfrac{4}{5}-\dfrac{\cancel{26}^{13}}{3}·\dfrac{1}{\cancel8_4}\right)=$

$\small =\left[\dfrac{15}{4}-\dfrac{9}{4} · \dfrac{2}{3}\right]·\left(\dfrac{4}{3} · \dfrac{5}{4}-\dfrac{13}{3}·\dfrac{1}{4}\right)=$

$\small =\left[\dfrac{15}{4}-\dfrac{\cancel9^3}{\cancel4_2} · \dfrac{\cancel2^1}{\cancel3_1}\right]·\left(\dfrac{\cancel4^1}{3} · \dfrac{5}{\cancel4_1}-\dfrac{13}{12}\right)=$

$\small =\left[\dfrac{15}{4}-\dfrac{3}{2} · \dfrac{1}{1}\right]·\left(\dfrac{1}{3} · \dfrac{5}{1}-\dfrac{13}{12}\right)=$

$\small =\left[\dfrac{15}{4}-\dfrac{3}{2} \right]·\left(\dfrac{5}{3}-\dfrac{13}{12}\right)=$

$\small =\left[\dfrac{15-6}{4} \right]·\left(\dfrac{20-13}{12}\right)=$

$\small =\dfrac{9}{4} ·\dfrac{7}{12}=$

$\small =\dfrac{\cancel9^3}{4} ·\dfrac{7}{\cancel{12}_4}=$

$\small =\dfrac{3}{4} ·\dfrac{7}{4}=$

$\small =\dfrac{21}{16}$

@gramor 👍👌👍

@remanzini_rinaldo - Grazie mille, buona giornata.



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(15/4 -9/4*2/3)*(4/3*5/4-26/3*1/8)

(15/4-6/4)*(5/3-13/12)

9/4*(20-13)/12

9*7/(4*12) 

21/16

@remanzini_rinaldo buon fine settimana! Ciao.

@mg..grazie, pure a te🤗



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