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Prisma quadrangolare
Spigolo di base $\small s= \dfrac{2p}{4} = \dfrac{68}{4} = 17\,cm;$
area di base $\small Ab= s^2 = 17^2 = 289\,cm^2;$
area laterale $\small Al= 2p×h = 68×22 = 1496\,cm^2;$
area totale $\small At= Al+2Ab = 1496+2×289 = 1496+578 = 2074\,cm^2.$