[Risolto] urgente

(2/3·(5/4))^2·(4/5)^2/x = (2/3 - 4/9)/((4/5 - 1/6 - 2/15)^3·(13/5 - 1))

(5/6)^2·(4/5)^2/x = 2/9/((1/2)^3·(8/5))

4/9/x = 2/9/(1/5)

x·2/9 = 4/9·(1/5)

x·2/9 = 4/45-----> x = 4/45·(9/2)

quindi: x = 2/5

((2/3 x 5/4)alla seconda x (4/5)alla seconda) : x = (2/3 - 4/9) : ((4/5 - 1/6 - 2/15)alla terza x (13/5 - 1)

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$\big[\big(\frac{2}{3}·\frac{5}{4}\big)^2·\big(\frac{4}{5}\big)^2\big] : x = \big(\frac{2}{3}-\frac{4}{9}\big) : \big[\big(\frac{4}{5}-\frac{1}{6}-\frac{2}{15}\big)^3·\big(\frac{13}{5}-1\big)\big]$ 

 $\big[\big(\frac{1}{3}·\frac{5}{2}\big)^2·\frac{16}{25}\big] : x = \big(\frac{6-4}{9}\big) : \big[\big(\frac{24-5-4}{30}\big)^3·\big(\frac{13-5}{5}\big)\big]$ 

 $\big[\big(\frac{5}{6}\big)^2·\frac{16}{25}\big] : x = \frac{2}{9} : \big[\big(\frac{15}{30}\big)^3·\frac{8}{5}\big]$ 

 $\big[\frac{25}{36}·\frac{16}{25}\big] : x = \frac{2}{9} : \big[\big(\frac{1}{2}\big)^3·\frac{8}{5}\big]$ 

 $\big[\frac{1}{9}·\frac{4}{1}\big] : x = \frac{2}{9} : \big[\frac{1}{8}·\frac{8}{5}\big]$ 

 $\frac{4}{9} : x = \frac{2}{9} : \big[\frac{1}{1}·\frac{1}{5}\big]$ 

 $\frac{4}{9} : x = \frac{2}{9} : \frac{1}{5}$ 

 $x = \frac{4}{9}·\frac{1}{5} : \frac{2}{9}$ 

 $x = \frac{4}{45}·\frac{9}{2}$ 

$x = \frac{2}{5}·\frac{1}{1}$ 

$x = \frac{2}{5}$