{(x + y) * [(x + y) + (x − y)] − 2xy} : [(− 2) * (− x)alla2]Risultato: − 1
@MichelaMc
{(x+y) * [2x] - 2xy} : (-2x²) =
= (2x² + 2xy-2xy)/(-2x²) = 2x² / (-2x²) = - 1
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