problema di fisica

F1 modulo di F1, F2 modulo di F2 e F modulo di F

F1 = 9*10^9*2*10^-8*(1.6*10^-19)/(x)^2
F2 = 9*10^9*1.2*10^-8*(1.6*10^-19)/(5*10^-2-x)^2
F = F1 + F2
L = -deltaU = intg(da1cm a 4cm)Fdx

integral_0.01^0.04 ((9×10^9 2×10^(-8) 1.6×10^(-19))/(5×10^(-2) - x)^2 + (9×10^9 1.2×10^(-8) 1.6×10^(-19))/x^2) dx = 3.456×10^-15 = deltaK = 9.11*10^-31*v^2/2

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verifichiamo ... Ua - Ub = k

Ua = kq1*|q|/(d-4*10^-2)+ kq2*|q|/(d-1*10^-2)= ~ 9*10^9*1.6*10^-19 (2*10^-8 / (5*10^-2-4*10^-2) - 1.2*10^-8/(5*10^-2-1*10^-2)) = 9×10^9 × 1.6×10^(-19) ((2×10^(-8))/(5×10^(-2) - 4×10^(-2)) - (1.2×10^(-8))/(5×10^(-2) - 1×10^(-2)))= +2.448 × 10^-15

Ub = kq2*|q|/(d-4*10^-2)+kq1*|q|/(d-1*10^-2)) = 9×10^9×1.6×10^(-19) ((2×10^(-8))/(5×10^(-2) - 1×10^(-2)) - (1.2×10^(-8))/(5×10^(-2) - 4×10^(-2))) = -1.008 × 10^-15

L = -deltaU = - (Ub - Ua) = Ua - Ub = 2.448 × 10^-15 - (-1.008 × 10^-15 )=  3.456 * 10^-15 = m*v^2/2 =9.11*10^-31*v^2/2