Numeri 300 e 301
A= [(DC+AB)•CH] / 2 --> DC+AB = 2A/CH= 12 cm
DC = (DC+AB)/6= 12/6= 2 cm
AB = DC•5= 2•5= 10 cm
DC+AB= 2A/CH= 20 cm
CD= (DC+AB)/4= 5cm
AB= CD•3= 15 cm
BC= CD+3= 8 cm
2p= 2CD+CB+AB= 2•5+8+15=33 cm
Grazie
2A = (AB+CD)*CH
(AB+CD) = 40*2/4 = 20 cm
20 = CD+3CD = 4CD
CD = 20/4 = 5 cm
AB = 3*5 = 15 cm
BC = CD+3 = 5+3 = 8 cm
AD = CD = 5 cm
perimetro 2p = AB+BC+CD+AD = 20+8+5 = 33 cm
(AB+CD) = 54*2/9 = 12 cm
12 = CD+5CD = 6CD
CD = 12/6 = 2 cm
AB = 2*5 = 10 cm
Home
Profilo
Menu