[Risolto] Potete gentilmente darmi una mano in questa espressione? Grazie

============================================================

$\left\{\left(-\frac{5}{3}\right)^2+\left[\left(\frac{1}{3}+\frac{1}{6}\right)^3÷\left(-\frac{1}{2}\right)^2-\frac{5}{4}\right]·\left(1+\frac{4}{3}\right)-2^{-2}\right\}÷\left(\frac{3}{7}\right)^{-2}-\frac{1}{7}=$

$=\left\{\frac{25}{9}+\left[\left(\frac{2+1}{6}\right)^3÷\left(-\frac{1}{2}\right)^2-\frac{5}{4}\right]·\left(\frac{3+4}{3}\right)-\left(\frac{1}{2}\right)^2\right\}÷\left(\frac{7}{3}\right)^2-\frac{1}{7}=$

$=\left\{\frac{25}{9}+\left[\left(\frac{\cancel3^1}{\cancel6_2}\right)^3÷\left(-\frac{1}{2}\right)^2-\frac{5}{4}\right]·\frac{7}{3}-\frac{1}{4}\right\}÷\frac{49}{9}-\frac{1}{7}=$

$=\left\{\frac{25}{9}+\left[\left(\frac{1}{2}\right)^3÷\left(-\frac{1}{2}\right)^2-\frac{5}{4}\right]·\frac{7}{3}-\frac{1}{4}\right\}·\frac{9}{49}-\frac{1}{7}=$

$=\left\{\frac{25}{9}+\left[\left(\frac{1}{2}\right)^{3-2}-\frac{5}{4}\right]·\frac{7}{3}-\frac{1}{4}\right\}·\frac{9}{49}-\frac{1}{7}=$

$=\left\{\frac{25}{9}+\left[\left(\frac{1}{2}\right)^1-\frac{5}{4}\right]·\frac{7}{3}-\frac{1}{4}\right\}·\frac{9}{49}-\frac{1}{7}=$

$=\left\{\frac{25}{9}+\left[\frac{1}{2}-\frac{5}{4}\right]·\frac{7}{3}-\frac{1}{4}\right\}·\frac{9}{49}-\frac{1}{7}=$

$=\left\{\frac{25}{9}+\left[\frac{2-5}{4}\right]·\frac{7}{3}-\frac{1}{4}\right\}·\frac{9}{49}-\frac{1}{7}=$

$=\left\{\frac{25}{9}+\left[-\frac{3}{4}\right]·\frac{7}{3}-\frac{1}{4}\right\}·\frac{9}{49}-\frac{1}{7}=$

$=\left\{\frac{25}{9}-\frac{\cancel3^1}{4}·\frac{7}{\cancel3_1}-\frac{1}{4}\right\}·\frac{9}{49}-\frac{1}{7}=$

$=\left\{\frac{25}{9}-\frac{1}{4}·\frac{7}{1}-\frac{1}{4}\right\}·\frac{9}{49}-\frac{1}{7}=$

$=\left\{\frac{25}{9}-\frac{7}{4}-\frac{1}{4}\right\}·\frac{9}{49}-\frac{1}{7}=$

$=\left\{\frac{100-63-9}{36}\right\}·\frac{9}{49}-\frac{1}{7}=$

$=\frac{\cancel{28}^7}{\cancel{36}_9}·\frac{9}{49}-\frac{1}{7}=$

$=\frac{\cancel7^1}{\cancel9_1}·\frac{\cancel9^1}{\cancel{49}_7}-\frac{1}{7}=$

$=\frac{1}{1}·\frac{1}{7}-\frac{1}{7}=$

$=\frac{1}{7}-\frac{1}{7}=$

$=0$

Sì, posso.