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N° 82

  

0

13-{8x15-[(7x5+5)÷8+20÷(28÷4-3)]}÷11

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1

13-{8x15-[(7x5+5)÷8+20÷(28÷4-3)]}÷11

$13-{8×15-[(35+5)÷8+20÷(7-3)]}÷11$

$13-{120-[40÷8+20÷4]}÷11$

$13-{120-(5+5)}÷11$

$13-{120-10}÷11$

$13-110÷11$

$13-10=3$

 



0

$13-\{8×15-[(7×5+5) ÷ 8+20÷(28÷4-3)]\}÷11$ =

= $13-\{120-[(35+5) ÷ 8+20÷(7-3)]\}÷11$ =

= $13-\{120-[40 ÷ 8+20÷4]\}÷11$ =

= $13-\{120-[5+5]\}÷11$ =

= $13-\{120-10\}÷11$ =

= $13-110÷11$ =

= $13-10$ =

= $3$

 

 

 



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