606)
$-(+15)^0+(-4)^2+2·(+3)^3-8^2$ =
= $-1+16+2·27-64$ =
= $15+54-64= 5$
607)
$[3·(-4)^2-7·(-5+3)^2] : 5 -(-2)^2$ =
= $[3·16-7·(-2)^2] : 5 -4$ =
= $[48-7·4] : 5 -4$ =
= $[48-28] : 5 -4$ =
= $20 : 5 -4$ =
= $4-4 = 0$.
606)
-(15)^0+(-4)^2+2*(3)^3-8^2=
-1+16+2*27-64=
=-1+16+54-64= +5
607)
[3*(-4)^2-7*(-5+3)^2]:5-(-2)^2=
=[3*16-7*(-2)^2]:5-4=
=[48-28]:5-4=
=20:5-4=
=4-4=0
609)
$\frac{1}{5}·\big(\frac{1}{8}-\frac{3}{4}\big) : \big(-\frac{1}{4}\big)^2-(-2)^2·\big(1-\frac{1}{2}\big)^3·\big(\frac{1}{7}+\frac{2}{3}\big)^0-\frac{1}{2}$ =
= $\frac{1}{5}·\big(\frac{1-6}{8}\big) : \frac{1}{16}-4·\big(\frac{2-1}{2}\big)^3·1-\frac{1}{2}$ =
= $\frac{1}{5}·\big(-\frac{5}{8}\big)·16 - 4·\big(\frac{1}{2}\big)^3-\frac{1}{2}$ =
= $\frac{1}{1}·\big(-\frac{1}{8}\big)·16 - 4·\frac{1}{8}-\frac{1}{2}$ =
= $-\frac{1}{1}·2 - 1·\frac{1}{2}-\frac{1}{2}$ =
= $ -2-\frac{1}{2}-\frac{1}{2}$ =
= $\frac{-4-1-1}{2}$ =
= $-\frac{6}{2}=-3$
610)
$\big(\frac{3}{4}+1\big)^3 : \big[\big(2-\frac{1}{8}\big)·\big(\frac{4}{3}-\frac{2}{5}\big)\big]-1-\frac{1}{16}$ =
= $\big(\frac{3+4}{4}\big)^3 : \big[\big(\frac{16-1}{8}\big)·\big(\frac{20-6}{15}\big)\big]-1-\frac{1}{16}$ =
= $\big(\frac{7}{4}\big)^3 : \big[\frac{15}{8}·\frac{14}{15}\big]-1-\frac{1}{16}$ =
= $\frac{343}{64} : \big[\frac{1}{4}·\frac{7}{1}\big]-1-\frac{1}{16}$ =
= $\frac{343}{64} : \frac{7}{4}-1-\frac{1}{16}$ =
= $\frac{343}{64}·\frac{4}{7}-1-\frac{1}{16}$ =
= $\frac{49}{16}·\frac{1}{1}-1-\frac{1}{16}$ =
= $\frac{49}{16}-1-\frac{1}{16}$ =
= $\frac{49-16-1}{16}= \frac{32}{16}=2$ =