(8x^3-4x+1)÷(x-1/2)
(8x^3-4x+1)÷(x-1/2)
499
punti
Livello 1
n° 462
$\dfrac{8x^3-4x+1}{x-\frac{1}{2}}=$
$= \dfrac{\cancel{(2x-1)}(4x^2+2x-1)}{\frac{1}{2}\cancel{(2x-1)}}=$
$= \dfrac{4x^2+2x-1}{\frac{1}{2}}=$
$= 2(4x^2+2x-1)=$
$= 8x^2+4x-2$
68270
punti
Genius I