(2/3+x)÷x=1/2÷1/3
(2/3+x)÷x=1/2÷1/3
(2/3+x)÷x=1/2÷1/3
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$\big(\frac{2}{3}+x\big)÷x = \frac{1}{2}÷\frac{1}{3}$
applica lo scomporre:
$\big(\frac{2}{3}+x-x\big)÷x = \big(\frac{1}{2}-\frac{1}{3}\big)÷\frac{1}{3}$
$\frac{2}{3}÷x = \big(\frac{3-2}{6}\big)÷\frac{1}{3}$
$\frac{2}{3}÷x = \frac{1}{6}÷\frac{1}{3}$
$x = \dfrac{\frac{2}{3}×\frac{1}{3}}{\frac{1}{6}}$
$x = \dfrac{\frac{2}{9}}{\frac{1}{6}}$
$x = \frac{2}{9}×6$
$x = \frac{12}{9}$
$x = \dfrac{4}{3}$
(2/3+x) ÷ x = 1/2 ÷ 1/3
x/2 = (2/3+x)*1/3
x/2 = 2/9+x/3
x/6 = 2/9
x = 12/9 = 4/3