3/8x-1/8-1/4x=3/4x+3/2x-2
3/8x-1/8-1/4x=3/4x+3/2x-2
220)
$\dfrac{3}{8}x -\dfrac{1}{8} -\dfrac{1}{4}x = \dfrac{3}{4}x +\dfrac{3}{2}x -2$
mcm= 8 quindi moltiplica tutto per 8 ed elimini i denominatori:
$3x-1-2x = 6x+12x-16$
$x-1 = 18x-16$
$x-18x = -16+1$
$-17x = -15$
$17x = 15$
$x= \dfrac{15}{17}$.