[Risolto] N° 133

$[(1/6-3/5)÷(2/3-1)]÷[(1/10÷3/4)x1/2$

$[(\frac{5-18}{30})÷(\frac{2-3}{3})]÷[\frac{1}{10}×\frac{4}{3})×\frac{1}{2}$

$[(\frac{-13}{30})÷(\frac{-1}{3})]÷[\frac{1}{5}×\frac{2}{3}]×\frac{1}{2}$

$[(\frac{-13}{30})÷(\frac{-1}{3})]÷[\frac{2}{15}]×\frac{1}{2}$

$(\frac{-13}{30})×(-\frac{3}{1})]×[\frac{15}{2}]×\frac{1}{2}$

$\frac{13}{10}×[\frac{15}{2}]×\frac{1}{2}$

$\frac{195}{40}=\frac{39}{2}]$

N° 133

[(1/6-3/5)÷(2/3-1)]÷[(1/10÷3/4)×1/2]

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$\bigg[\bigg(\dfrac{1}{6}-\dfrac{3}{5}\bigg)÷\bigg(\dfrac{2}{3}-1\bigg)\bigg]÷\bigg[\bigg(\dfrac{1}{10}÷\dfrac{3}{4}\bigg)·\dfrac{1}{2}\bigg]=$

$=\bigg[\bigg(\dfrac{5-18}{30}\bigg)÷\bigg(\dfrac{2-3}{3}\bigg)\bigg]÷\bigg[\dfrac{1}{10}·\dfrac{4}{3}·\dfrac{1}{2}\bigg]=$

$=\bigg[\bigg(-\dfrac{13}{30}\bigg)÷\bigg(-\dfrac{1}{3}\bigg)\bigg]÷\bigg[\dfrac{1}{5}·\dfrac{2}{3}·\dfrac{1}{2}\bigg]=$

$=\bigg[\bigg(-\dfrac{13}{30}\bigg)÷\big(-3\big)\bigg]÷\bigg[\dfrac{1}{5}·\dfrac{1}{3}·\dfrac{1}{1}\bigg]=$

$=\bigg[\dfrac{39}{30}\bigg]÷\dfrac{1}{15}=$

$= \dfrac{13}{10}·15=$

$= \dfrac{195}{10}=$

$= \dfrac{39}{2}$