3·(x^2 - 4·√3) - 8·x·(√3 - 1) + 19 = 0
3·x^2 - 8·x·(√3 - 1) - 12·√3 + 19 = 0
a = 3
b = - 8·(√3 - 1)
c = 19 - 12·√3
Δ = (- 8·(√3 - 1))^2 - 4·3·(19 - 12·√3)
Δ = (256 - 128·√3) - (228 - 144·√3)
Δ = 16·√3 + 28
√Δ = √(16·√3 + 28)----> √Δ = 2·√3 + 4
x1 = (8·(√3 - 1) - (2·√3 + 4))/6
x1 = √3 - 2
x2 = (8·(√3 - 1) + (2·√3 + 4))/6
x2 = (5·√3 - 2)/3