mi serve un aiuto con queste espressioni, ringrazio in anticipo

√(((2/5 + 1 - 1/2)^2·(10/9) + 1)/(10/3·(3/8)·(8/5·(1/8) + 1/2)))=

da approssimare a meno di 1/100=0.01

=√(((9/10)^2·(10/9) + 1)/(10/3·(3/8)·(1/5 + 1/2)))=

=√((9/10 + 1)/(10/3·(3/8)·(7/10)))=

=√(19/10/(7/8))=

=√(76/35)=1.473576795---> =1.47

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$\small \sqrt{\left[\left(\dfrac{2}{5}+1-\dfrac{1}{2} \right)^2·\dfrac{10}{9}+1\right]÷\left[\dfrac{\cancel{10}^5}{\cancel3_1}·\dfrac{\cancel3^1}{\cancel8_4}·\left(\dfrac{\cancel8^1}{5}·\dfrac{1}{\cancel8_1}+\dfrac{1}{2}\right)\right]}^{^{0,01}} =$

$\small = \sqrt{\left[\left(\dfrac{4+10-5}{10} \right)^2·\dfrac{10}{9}+1\right]÷\left[\dfrac{5}{1}·\dfrac{1}{4}·\left(\dfrac{1}{5}·\dfrac{1}{1}+\dfrac{1}{2}\right)\right]} =$

$\small = \sqrt{\left[\left(\dfrac{9}{10} \right)^2·\dfrac{10}{9}+1\right]÷\left[\dfrac{5}{4}·\left(\dfrac{1}{5}+\dfrac{1}{2}\right)\right]} =$

$\small = \sqrt{\left[\dfrac{\cancel{81}^9}{\cancel{100}_{10}} ·\dfrac{\cancel{10}^1}{\cancel9_1}+1\right]÷\left[\dfrac{5}{4}·\left(\dfrac{2+5}{10}\right)\right]} =$

$\small = \sqrt{\left[\dfrac{9}{10} ·\dfrac{1}{1}+1\right]÷\left[\dfrac{\cancel5^1}{4}·\dfrac{7}{\cancel{10}_2}\right]} =$

$\small = \sqrt{\left[\dfrac{9}{10} +1\right]÷\left[\dfrac{1}{4}·\dfrac{7}{2}\right]} =$

$\small = \sqrt{\left[\dfrac{9+10}{10} \right]÷\dfrac{7}{8}} =$

$\small = \sqrt{\dfrac{19}{\cancel{10}_5} · \dfrac{\cancel8^4}{7}} =$

$\small = \sqrt{\dfrac{19}{5} · \dfrac{4}{7}} =$

$\small = \sqrt{\dfrac{76}{35} } = 1,473576...$

risultato approssimato al secondo decimale:

$\small = 1,47$