[Risolto] Matematica

$x/(\frac{9}{4}-\frac{3}{8}+3)=(2+\frac{8}{3})/(9^2+\sqrt{10^2})$

$x/(\frac{18-3+24}{8})=(\frac{6+8}{3})/(81+10)$

$x/(\frac{39}{8})=(\frac{14}{3})/91$

$x=\frac{\frac{39}{8}*\frac{14}{3}}{91}=\frac{\frac{91}{4}}{91}=\frac{1}{4}$