Spiegare i passaggi.
∫((2·x - 1)/(x^2 - 2·x + 1))dx=
=∫(1/(x - 1)^2)dx + ∫(2/(x - 1)) dx=
=- 1/(x - 1) + ∫(2/(x - 1))dx=
=- 1/(x - 1) + 2·∫(1/(x - 1))dx=
=- 1/(x - 1) + 2·LN|x - 1|=
=2·LN(x - 1) - 1/(x - 1) + C
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