Grazie
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$\small\text{Area parte colorata:}$
$\small A= (4+x)(x+1+x+2)-(x(x+1)+3x)$
$\small A= (4+x)(2x+3)-(x^2+x+3x)$
$\small A= 8x+12+2x^2+3x-(x^2+4x)$
$\small A= 11x+12+2x^2-x^2-4x$
$\small A= 7x+12+x^2$
$\small A= x^2+7x+12\; \Longrightarrow\; = (x+4)(x+3).$
$\small\text{Perimetro del rettangolo:}$
$\small 2p= 2(4+x)+(x+1+x+2)+3+(x+1+x+2)-3$
$\small 2p= 8+2x+2x+3+3+2x\cancel{+3}\cancel{-3}$
$\small 2p= 14+6x$
$\small 2p= 6x+14 \;\Longrightarrow \;= 2(3x+7).$
perimetro 2p = 2(4+x)+2(2x+3) = 8+2x+4x+6 = 6x+14 = 2(3x+7)
area colorata Ac= (4+x)(2x+3)-x^2-x-3x
Ac = 8x+12+2x^2+3x-x^2-3x = x^2+7x+12 = (x+3)(x+4)
Lati del rettangolo grande:
base = (x + 2) + (x + 1);
altezza = 4 + x;
base = x + x + 2 + 1 = 2x + 3;
Perimetro = 2 * (b + h) = 2 * (2x + 3 + 4 + x) ;
Perimetro = 2 * (3x + 7) = 6x + 14;
Area rettangolo = (2x + 3) * (4 + x);
Area rettangolo grande =
A = 8x + 2x^2 + 12 + 3x;
A = 2x^2 + 11 x + 12;
Area dei rettangolini bianchi: A1 + A2;
A1 = 3 x;
A2 = x * (x + 1) = x^2 + x;
A1 + A2 = 3x + x^2 + x = x^2 + 4x;
Area gialla = A - (A1 + A2);
Area gialla = 2x^2 + 11 x + 12 - (x^2 + 4x);
Area gialla = 2x^2 + 11 x + 12 - x^2 - 4x ;
Area gialla = x^2 + 7x + 12.
Ciao @michele-09