Espressioni

mcm(3;9) = 9;   potenze di 3:   9 = 3^2;   81 = 9 * 9 = 3^2 * 3^2 = 3^4;

[(12 - 11)/9]^2 + 2/9 + (1/3)^6 x (3^2)^10  x 1 / [(3^4)^4] - 1/3^2 =

= (1/9)^2 + 2/9 + (1/3)^6 x  3^20  x 1/(3^16) - 1/9 =

= 1/81 + 2/9 + 3^20 /(3^6 x 3^16) - 1/9 =

= 1/81 + 2/9 + 3^20 / (3^22) - 1/9 =

= 1/81 + 2/9 + 1 / (3^2) - 1/9 =

= 1/81 + 2/9 + 1/9 - 1/9 =

mcm = 81 = 9 * 9;

= 1/81 + 18/81 + 9/81 - 9/81 =

= 19/81.

Ciao @giacomo77

(4/3 - 11/9)^2 + 2/9 + (1/3)^6·9^10·(1/81^4) - 1/3^2=

=(1/9)^2 + 2/9 + (1/3)^6·3^20·(1/3^16) - 1/3^2=

=1/81 + 2/9 + 1/9 - 1/9=

=19/81

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$\small \left(\dfrac{4}{3}-\dfrac{11}{9}\right)^2+\dfrac{2}{9}+\left(\dfrac{1}{3}\right)^6·9^{10}·\dfrac{1}{81^4}-\dfrac{1}{3^2} = $

$\small = \left(\dfrac{12-11}{9}\right)^2+\dfrac{2}{9}+\dfrac{1}{3^6}·9^{10}·\dfrac{1}{9^4·9^4}-\dfrac{1}{9} = $

$\small = \left(\dfrac{1}{9}\right)^2+\dfrac{2}{9}+\dfrac{1}{3^6}·9^{10-4-4}·1-\dfrac{1}{9} = $

$\small = \dfrac{1}{81}+\dfrac{2}{9}+\dfrac{1}{729}·9^2-\dfrac{1}{9} = $

$\small = \dfrac{1}{81}+\dfrac{2}{9}+\dfrac{1}{\cancel{729}_9}·\cancel{81}^1-\dfrac{1}{9} = $

$\small = \dfrac{1}{81}+\dfrac{2}{9}\cancel{+\dfrac{1}{9}}\cancel{-\dfrac{1}{9}} = $

$\small = \dfrac{1+18}{81} = $

$\small = \dfrac{19}{81}$

((12-11)/9)^2+2/9+(1/9)^3*9^10*(1/9)^8-1/9

1/81+2/9+(1/9)^3*9^2-1/9

19/81+1/9-1/9 

19/81 

((3*(54-14+21)/21*7/5*1/61)^3+4/25)*5/7

((3*61/21*7/5*1/61)^3+4/25)*5/7 

(1/5)^3+20/5^3)*5/7

21/125*5/7 

3/25

1/6+3/20 : (36/5*((12-9-2)/6)^2-1/4*2/3)+1/5*20/2

1/6+3/20 : (36/5*1/36-1/6)+20/15

1/6+3/20 :(1/5-1/6)+20/15

1/6+3/20*30/1+20/15

1/6+9/2+4/3

(1+27+8)/6

36/6

1

(4/9)-(8+24)/9+49/9)*(1/49+(-3/7-4/49)

4/9-(32/9+49/9)*(1-21-4)/49

4/9-(81/9*-24/49)

4/9+9*24/49

2140/441 ?