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Cortesemente la 62-65

Non riesco a capire dove sbaglio

IMG 20260204 WA0027

 

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3

(11^2·3 - 4^4 - 5^2 - 1)/9 - (3^4·2 - 7^2·3)/5=

=(121·3 - 256 - 25 - 1)/9 - (81·2 - 49·3)/5=

=(363 - 256 - 25 - 1)/9 - (162 - 147)/5=

=81/9 - 15/5= 9 - 3 = 6

------------------------------------------

13 + (3^2 + 3)/(3·2^2 - 6) + 5 - (4^2 + 3^2)/5=

=13 + (9 + 3)/(3·4 - 6) + 5 - (16 + 9)/5=

=13 + 12/(12 - 6) + 5 - 25/5=

=13 + 2 + 5 - 5 = 15

@lucianop Grazie

@ozuna

Di nulla. Buona sera.



3

62)

(11^2 x 3 - 4^4 - 5^2 - 1) : 9 - (3^4 x 2 - 7^2 x 3) : 5 =

Prima le potenze, poi le moltiplicazioni:

= (121 x 3 - 256 - 25 - 1) : 9 - (81 x 2 - 49 x 3) : 5 =

= (363 - 256 - 25 - 1) : 9 - (162 - 147) : 5 =

= 81 : 9 - 15 : 5 =

= 9 - 3 =

=  6 .

 

65)

13 + (3^2 + 3) : (3 x 2^2 - 6) + 5 - (4^2 + 3^2) : 5 =

= 13 + (9 + 3) : (3 x 4 - 6) + 5 - (16 + 9) : 5 =

= 13 + 12 : (12 - 6) + 5 - 25 : 5 =

= 13 + 12 : 6 + 5 - 5 =

= 13 + 2 + 5 - 5 =

= 15.

Ciao  @ozuna

 



2

62)

$\small (11^2×3-4^4-5^2-1)÷9-(3^4×2-7^2×3)÷5 =$

$\small = (121×3-256-25-1)÷9-(81×2-49×3)÷5 =$

$\small = (363-256-25-1)÷9-(162-147)÷5 =$

$\small = 81÷9-15÷5 =$

$\small = 9-3 = 6$

 

65)

$\small 13+(3^2+3)÷(3×2^2-6)+5-(4^2+3^2)÷5 =$

$\small = 13+(9+3)÷(3×4-6)+5-(16+9)÷5 =$

$\small = 13+12÷(12-6)+5-25÷5 =$

$\small = 13+12÷6\cancel{+5}\cancel{-5} =$

$\small = 13+2 = 15$



0
61

=======================================================

$\small (9^2×3-6^2×4+1)÷10+(8^2×3-5^2×6)÷7 =$

$\small = (81×3-36×4+1)÷10+(64×3-25×6)÷7 =$

$\small = (243-144+1)÷10+(192-150)÷7 =$

$\small = 100÷10+42÷7 =$

$\small = 10+6 = $

$\small = 16$



0
60

=======================================================

60)

$\small (8^2÷4+2^2×3)÷7+3^2-6×2 =$

$\small = (64÷4+4×3)÷7+9-12 =$

$\small = (16+12)÷7+9-12 =$

$\small = 28÷7+9-12 =$

$\small = 4+9-12 =$

$\small = 1$



0
63

=============================================================

$\small [5^3÷(4^2+3^2)+7]÷4+4^2 = $

$\small = [125÷(16+9)+7]÷4+16 = $

$\small = [125÷25+7]÷4+16 = $

$\small = [5+7]÷4+16 = $

$\small = 12÷4+16 = $

$\small = 3+16 = $

$\small = 19$



0
64 a

==============================================================

$\small (5^2-5)-(4^2+2)÷6+(2^3-3)×3-4×8 =$

$\small = (25-5)-(16+2)÷6+(8-3)×3-32 = $

$\small = 20-18÷6+5×3-32 = $

$\small = 20-3+15-32 = $

$\small = 0 $



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