a. x-3(x-1)-(x+1)=-3(x-1)
b. 2x+3(x-2)-(x-1)+x=2x+1
a. x-3(x-1)-(x+1)=-3(x-1)
b. 2x+3(x-2)-(x-1)+x=2x+1
a) x-3(x-1)-(x+1)=-3(x-1)
x-3x+3-x-1=-3x+3
0x+3-1=3
2=3
a)
$x-3(x-1)-(x+1) = -3(x-1)$
$x-3x+3-x-1 = -3x +3$
$-3x +2 = -3x +3$
$-3x+3x = 3-2$
$0=1$
equazione impossibile.
b)
$2x+3(x-2)-(x-1)+x = 2x +1$
$2x +3x -6 -x +1 +x = 2x +1$
$5x -5 = 2x +1$
$5x -2x = 1+5$
$3x = 6$
$x = \frac{6}{3}$
$x = 2$