equazioni

a) x-3(x-1)-(x+1)=-3(x-1)

x-3x+3-x-1=-3x+3

0x+3-1=3

2=3

a)

$x-3(x-1)-(x+1) = -3(x-1)$

$x-3x+3-x-1 = -3x +3$

$-3x +2 = -3x +3$

$-3x+3x = 3-2$

$0=1$

equazione impossibile.

b)

$2x+3(x-2)-(x-1)+x = 2x +1$

$2x +3x -6 -x +1 +x = 2x +1$

$5x -5 = 2x +1$

$5x -2x = 1+5$

$3x = 6$

$x = \frac{6}{3}$

$x = 2$