[Risolto] Derivte

lim_x->3+ (x - 3) ln (x^2 - 9) =

= lim_x->3+ ln (x^2 - 9)/(1/(x-3)) =

= lim_x->3+ 1/(x^2 - 9) * 2x /(- 1/(x - 3)^2) =

= lim_x->3+ -2x (x-3)^2/((x-3)(x+3)) =

= -6 lim_x->3+ (x-3)/(x+3) = -6*0 = 0

é il solito trucco