Derivata 1 ^ e 2^

Question

[attach]118874[/attach] Spiegare gentilmente i ragionamenti, i passaggi e argomentare.

LucianoP · Accepted Answer

y = LN(LN(x))----> y'=(LN(x)' /LN(x) y' =1/(x·LN(x)) -------------------- 1/LN(x)-----> y'= - (LN(x))'/LN(x)^2 y'= - 1/(x·LN(x)^2) Quindi: y'= =1/(x·LN(x)) - 1/(x·LN(x)^2)= =(LN(x) - 1)/(x·LN(x)^2) ----------------- y''= =2/(x^2·LN(x)^3) - 1/(x^2·LN(x))= =(2 - LN(x)^2)/(x^2·LN(x)^3)

Derivata 1 ^ e 2^

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