em = 3,14/2*2^2*10^-4*100*10 = 0,628 V
I = em/r = 628/50 = 12,56 mA
Q = I*t = 12,56*0,1 = 1,256 mCoulomb
...non lo so!!!
mi limito alla soluzione.
deltaphic = N*B*S =100*2*(1*10^-2)^2*pi
deltat = 100 *10^-3 = 0.1 s
|emedia| = deltaphic/deltat = 2pi*10^-2/0.1 = 0.62831853... =~ 0.628 V
i = 0.628/50 = 0.012566... =~ 0.0126 A = 12.6 mA
q = i*deltat = 0.0126*0.1 = 1.26 mC