Ciao, potreste aiutarmi con questa espressione con le frazioni e i numeri relativi? Grazie

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$\left[\left(\frac{5}{6}-\frac{3}{2}\right)-\left(\frac{1}{8}-\frac{1}{5}-\frac{3}{10}\right)\right]-\left[\left(\frac{1}{2}+\frac{5}{6}\right)+\left(\frac{3}{8}-\frac{1}{2}\right)\right]=$

$=\left[\left(\frac{5-9}{6}\right)-\left(\frac{5-8-12}{40}\right)\right]-\left[\left(\frac{3+5}{6}\right)+\left(\frac{3-4}{8}\right)\right]=$

$=\left[\left(-\frac{\cancel4^2}{\cancel6_3}\right)-\left(-\frac{\cancel{15}^3}{\cancel{40}_8}\right)\right]-\left[\frac{\cancel8^4}{\cancel6_3}+\left(-\frac{1}{8}\right)\right]=$

$=\left[\left(-\frac{2}{3}\right)-\left(-\frac{3}{8}\right)\right]-\left[\frac{4}{3}-\frac{1}{8}\right]=$

$=\left[\left(-\frac{2}{3}\right)+\frac{3}{8}\right]-\left[\frac{32-3}{24}\right]=$

$=\left[\frac{-16+9}{24}\right]-\frac{29}{24}=$

$=-\dfrac{7}{24}-\dfrac{29}{24}=$

$=-\dfrac{\cancel{36}^3}{\cancel{24}_2}=$

$= -\dfrac{3}{2}$