log_3 [3 * 3^(1/2) : 3^(1/3)] =
= log_3 3^(1 + 1/2 - 1/3) =
= log_3 3^((6 + 3 - 2)/6) =
= log_3 3^(7/6) =
= 7/6
log3 {[3*3^(1/2)]/[3^(1/3)]}= log3[3^(1+1/2-1/3)]=log3[3^(7/6)] => x= loga (b)
a^x=b
x=7/6
* log(3, 3*√3/∛3) =
= log(3, 3*√3) - log(3, ∛3) =
= log(3, 3) + log(3, √3) - log(3, ∛3) =
= log(3, 3^1) + log(3, 3^(1/2)) - log(3, 3^(1/3)) =
= 1 + 1/2 - 1/3 =
= 7/6 = 1.1(6) ~= 1.17