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[Risolto] calcolo del logaritmo

  

0
IMG20240319175810
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1

log_3 [3 * 3^(1/2) : 3^(1/3)] =

= log_3 3^(1 + 1/2 - 1/3) =

= log_3 3^((6 + 3 - 2)/6) =

= log_3 3^(7/6) =

= 7/6



1

log3 {[3*3^(1/2)]/[3^(1/3)]}= log3[3^(1+1/2-1/3)]=log3[3^(7/6)] => x= loga (b)

a^x=b 

x=7/6



0

* log(3, 3*√3/∛3) =
= log(3, 3*√3) - log(3, ∛3) =
= log(3, 3) + log(3, √3) - log(3, ∛3) =
= log(3, 3^1) + log(3, 3^(1/2)) - log(3, 3^(1/3)) =
= 1 + 1/2 - 1/3 =
= 7/6 = 1.1(6) ~= 1.17

 



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