[Risolto] Algebra

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mcm dei denominatori = 40 quindi moltiplicando tutto per 40 li elimini:

$25(2-x)+6(x+1) = 10(x+3)-16(x-1)-15x$

$50x-25x+6x+6 = 10x+30-16x+16-15x$

$-19x+56 = -21x+46$

$-19x+21x = 46-56$

$2x = -10$

$x= \dfrac{-10}{2}$

$x= -5$

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5·(2 - x)/8 + 3·(x + 1)/20 = (x + 3)/4 - 2·(x - 1)/5 - 3/8·x

(10 - 5·x)/8 + (3·x + 3)/20 = (x + 3)/4 - (2·x - 2)/5 - 3/8·x

(10 - 5·x)·5 + (3·x + 3)·2 = (x + 3)·10 - (2·x - 2)·8 - 3·x·5

(50 - 25·x) + (6·x + 6) = (10·x + 30) - (16·x - 16) - 15·x

56 - 19·x = 46 - 21·x

2·x = -10-------> x = -5