Es 125 Grazie
area convessa AôB = π*99^2*160/360 = 4.356π cm^2
area concava AôB = π*99^2*(360-160)/360 = 5.445π cm^2
area convessa CôD = π*21^2*72/360 = 88,20π cm^2
area concava CôD = π*21^2*(360-72)/360 = 352,80π cm^2
125)
a- Area settore circolare $A_{(AOB)} = \dfrac{r^2×\pi×\alpha}{360°} = \dfrac{99^2×\pi×160}{360}= 4356\pi\,cm^2.$
b- Area settore circolare $A_{(COD)} = \dfrac{r^2×\pi×\alpha}{360°} = \dfrac{21^2×\pi×72}{360}= \dfrac{441}{5}\pi\,cm^2.$