{27 - 3^x ≥ 0
{(1/5)^(x/2) < 25^(1/3)
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{x ≤ 3
{5^(- x/2) < 5^(2/3)
{- x/2 < 2/3---> x > - 4/3
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Soluzione: - 4/3 < x ≤ 3
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