non mi esce l’esercizio (il 69)
(R parallelo 1) + (R parallelo 2) = R equivalente;
(1/R1 + 1/R2)^-1 + ( 1/R3 + 1/R4 + 1/R5)^-1 = R equivalente;
(1/20 + 1/30)^-1 + (1/70 + 1/30 + 1/R5)^-1 = 20,4 Ω;
(3/60 + 2/60)^-1 + ( 3/210 + 7/210 + 1/R5)^-1 = 20,4;
(5/60)^-1 + (10/210 + 1/R5)^-1 = 20,4 ;
(1/12)^-1 + (1/21 + 1/R5)^-1 = 20,4 ;
12 + (1/21 + 1/R5)^-1 = 20,4 ;
(1/21 + 1/R5)^-1 = 20,4 - 12;
[(R5 + 21) / (21 * R5)]^-1 = 20,4 - 12;
21 * R5 / (R5 + 21) = 8,4;
21 R5 = 8,4 * (R5 + 21);
21 R5 = 8,4 R5 + 176,4;
21 R5 - 8,4 R5 = 176,4;
12,6 R5 = 176,4;
R5 = 176,4 / 12,6 = 14 Ω.
Ciao @alessiamoro
R1//R2+Rp = 20,4 ohm
(20*30)/(20+30) = 600/50 = 60/5 = 12 ohm
Rp = 20,4-12 = 8,4 ohm
Rp = 70 // 30 // R5
Rp' = 70//30 = 70*30/(70+30) = 2100/100 = 21 ohm
Rp = 8,4 = (Rp'//R5)
8,4 = 21*R5/(21+R5)
176,4 = R5(21-8,4)
R5 = 176,4/12,6 = 14,0 ohm
dò ad R il valore unitario
1) 1+2+3 = 6
2) 1//2//3 = 1/(1+1/2+1/3) = 0,(54)
3) 1+2//3 = 1+6/5 = 11/5 = 2,20
4) 2+1//3 = 2+3/4 = 11/4 = 2,75
5) 3+1//2 = 3+2/3 = 11/3 = 3,(6)
6) (1+2)//3 = 3//3 = 3/2 = 1,50
7) (1+3)//2 = 4//2 = 4/3 = 1,(3)
8) (2+3)//1 = 5//1 = 5/6 = 0,8(3)
0,(54) ; 0,8(3) ; 1,(3) ; 1,5 ; 2,20 ; 2,75 ; 3,6 ; 6