N. 5

Question

[(5/2)^4)×(3-1/2)^2] ×(5/2)^2 :[(-5/2)^6]^2 - 5/2=

SilvSilvSilv · Accepted Answer

$[( frac {5}{2})^4(3- frac {1}{2})^2]^2( frac {5}{2})^2÷[(- frac {5}{2})^6]^2- frac {5}{2}   $[( frac {5}{2})^4( frac {5}{2})^2]^2( frac {5}{2})^2÷(- frac {5}{2})^6]^2- frac {5}{2}   $[( frac {5}{2})^{4+2}]^2( frac {5}{2})^2÷[(- frac {5}{2})^6]^2- frac {5}{2}   $[( frac {5}{2})^6]^2( frac {5}{2})^2÷[(- frac {5}{2})^6]^2- frac {5}{2}   $( frac {5}{2})^{6*2}( frac {5}{2})^2÷[(- frac {5}{2})^6]^2- frac {5}{2}   $( frac {5}{2})^{12}( frac {5}{2})^2÷[(- frac {5}{2})^6]^2- frac {5}{2}   $( frac {5}{2})^{12+2}÷(- frac {5}{2})^{6*2}- frac {5}{2}   $( frac {5}{2})^{14}÷(- frac {5}{2})^{12}- frac {5}{2}   $( frac {5}{2})^{14-12}- frac {5}{2}   $( frac {5}{2})^{2}- frac {5}{2}   $( frac {25}{4})- frac {5}{2}   $( frac {25-10}{4})= frac {15}{4}

N. 5

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