n° 42

Question

[5^2 - (3^3 - 3^3 ÷ 3^2)] x [2^4 - (2^2 - 3)] - (2^4 - 2^0) ÷ 3

mg · Accepted Answer

[5^2 - (3^3 - 3^3 : 3^2)] x [2^4 - (2^2 - 3)] - (2^4 - 2^0) : 3 =

= [25 - (3^3 - 3^1)] x [2^4 - (4 - 3)] - (16 - 1) : 3 =

= [25 - 24] x [16 - 1] - 15 : 3 =

= 1 x 15 - 5 =

= 15 - 5 =

= 10.

Ciao @luigii

mg

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09/06/2025 11:59

LucianoP · Answer

(5^2 - (3^3 - 3^3/3^2))·(2^4 - (2^2 - 3)) - (2^4 - 2^0)/3= =(25 - (3^3 - 3))·(2^4 - 1) - 15/3= =(25 - 24)·15 - 5= =1·15 - 5 = 10

gramor · Answer

small [5^2-(3^3-3^3 : 3^2)]×[2^4-(2^2-3)]-(2^4-2^0) : 3=$    small [25-(27-3^{3-2})]×[16-(4-3)]-(16-1) : 3=$    small [25-(27-3^1)]×[16-1]-15 : 3=$    small =[25 - (27 - 3)] × 15 -5=$    small =[25 - 24] × 15 -5=$    small =1 × 15 -5=$    small =15 -5 = 10$

n° 42

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